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The ratio of contributions made by the e...

The ratio of contributions made by the electric field and magnetic field components to the intensity of the EM wave is………

A

`C:1`

B

`C^2:1`

C

`1:1`

D

`sqrtC:1`

Text Solution

Verified by Experts

The correct Answer is:
C
`I_e=epsi_0E_(rms)^2c`
`I_m=(B_(rms)^2)/(mu_0)c`
`therefore I_e/I_m=(E_(rms)/B_(rms))^2mu_0epsi_0=c^2 times 1/c^2=1 implies 1_e=I_m`
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