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de- Broglie wavelength associated with a...

de- Broglie wavelength associated with an electron, accelerating through a potential

A

gamma rays

B

X-rays

C

ultraviolet

D

visible region

Text Solution

Verified by Experts

The correct Answer is:
B
de Broglie wavelength
`lamda=h/p=1.227/sqrtV nm`
`lamda=1.227/sqrt100=1.227/10`
`therefore lamda=0.1227 nm`
This wavelength falls in the region of X-rays.
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