`t^@C` = (273 - t)K

Scientists uses the Kelvin scale (K) as an alternative temperature scale to degrees celsius (°C) by the relation T°C = (T+273)K. Convert the following to Kelvin: -273°C

Scientists uses the Kelvin scale (K) as an alternative temperature scale to degrees Celsius (°C) by the relation T°C = (T+273)K. Convert the following to Kelvin: -275°C

Scientists uses the Kelvin scale (K) as an alternative temperature scale to degrees celsius (°C) by the relation T°C = (T+273)K. Convert the following to Kelvin: -45°C

Scientists uses the Kelvin scale (K) as an alternative temperature scale to degrees celsius (°C) by the relation T°C = (T+273)K. Convert the following to Kelvin: -400°C

{:("Column-I ","Column-II "),("A) Hydrogen gas (P = 200 atm, T = 273K) ","P) Compressibility factor "!= 1 ),("B) Hydrogen gas "(P ~~ 0,T = 273K) ,"Q) Attractive forces are dominant "),("C)" CO_2 (P= 1 atm, T = 273K) ,"R)" PV = nRT ),("D) Real gas with very large molar volume ","S)" P(V - nb) = nRT ):}

Answer the following The absolute temperature (kelvin scale) T is related to the temperature T_C on the celsius scale by T_C = T - 273.15 . Why do we have 273.15 in this relation and not 273.16?