" 7."quad (4y+1)/(3)+(2y-1)/(2)-(3y-7)/(5)=(47)/(10)

Solve for x and y : (y+7)/(5)=(2y-x)/(4)+3x-5 (7-5x)/(2)+(3-4y)/(6)=5y-18

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

The distance of point of intersection of lines (x-4)/(1)=(x+3)/(-4)=(z-1)/(7) and (x-1)/(2)=(y+1)/(-3)=(z+10)/(8) from (1,-4,7) is

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

Simplify: ((1)/(3)y^(2)-(4)/(7)y+11)-((1)/(7)y-3+2y^(2))-((2)/(7)y-(2)/(3)y^(2)+2)

The point of intersection of the lines (x-5)/(3)=(y-7)/(-1)=(z+2)/(1) and (x+3)/(-36)=(y-3)/(2)=(z-6)/(4) is (A) (21,(5)/(3),(10)/(3))(B)(2,10,4)(C)(-3,3,6)(D)(5,7,-2)

Solve the following equaions for x and y log_(10)x+(1)/(2)log_(10)x+(1)/(4)log_(10)x+"...."=y " and " (1+3+5+"...."+(2y-1))/(4+7+10+"...."+(3y-1))=(20)/(7log_(10)x) .

Solve the following equaions for x and y log_(10)x+(1)/(2)log_(10)x+(1)/(4)log_(10)x+"...."=y " and " (1+3+5+"...."+(2y-1))/(4+7+10+"...."+(3y-1))=(20)/(7log_(10)x) .

If the LCM of the polynomials (y -3)^(a) (2y + 1)^(b) (y + 13)^(7) and (y -3)^(4) (2y +1)^(9) (y + 13)^(c) " is " (y - 3)^(6) (2y +1)^(10) (y + 13)^(7) , then the least value of a + b +c is

The point of intersection of the lines (x-5)/3=(y-7)/(-1)=(z+2)/1a n d=(x+3)/(-36)=(y-3)/2=(z-6)/4 is a. (21 ,5/3,(10)/3) b. (2,10 ,4) c. (-3,3,6) d. (5,7,-2)