The line 'x + 3y - 2 = 0' bisects the angle between a pair of straight lines of which one has equation 'x - 7y + 5 = 0' , then find equation of other line.

the line x+3y-2=0 bisects the angle between a pair of straight lines of which one has equation x-7y + 5 = 0 . The equation of the other line is :

the line x+3y-2=0 bisects the angle between a pair of straight lines of which one has equation x-7y + 5 = 0 . The equation of the other line is : (A) 3x+3y-1=0 (B) x-3y+2=0 (C) 5x+5y-3=0 (D) None of these

the line x+3y-2=0 bisects the angle between a pair of straight lines of which one has equation x-7y + 5 = 0 . The equation of the other line is : (A) 3x+3y-1=0 (B) x-3y+2=0 (C) 5x+5y-3=0 (D) None of these

The angle between the two straight line of a pair of straight line x^2 - y^2 - 2y - 1 = 0 is

Find the angles between the pairs of straight line x-y sqrt(3)=5 and sqrt(3)x+y=7

The equation of the pair of bisectors of the angles between two straight lines is,12x^(2)-7xy-12y^(2)=0. If the equation of one line is 2y-x=0, then the equation of the other line is: