A particle performing S.H.M. about their mean position with the equation of velocity is given by `4v^(2)=25-x^(2)`, then the period of motion is

A particle is performing a linear S.H.M about the mean position with the equation of velocity given by 4v^(2)-25-x^(2) . Then the period of motion is

The particle performing S.H.M., about mean position it has

A particle performing S.H.M. about equilibrium position. Then the velocity of the particle is

The kinetic energy of a particle performing S.H.M. at mean position is

The velocity of a particle performing S.H.M. at mean position is

A body performing SHM about its mean position with period 24 s, after 4 s its velocity is pi m//s , then its path will be

The particle performing S.H.M. about mean position, displacement and acceleration have initial phase difference of

The velocity of a particle performing S.H.M. at any position

The velocity of a particle performing S.H.M. at extreme position is