Electrons with de - Brogli wavelengtyh `lambda` fall on the target in
an X-ray tube.The cut off wavelength of the emitted Xrays is
(a) `lambda_0 = (2mclambda^2)/(h)` (b)`lambda_0 = (2h)/(mc)`
(c ) `lambda_0 (2m^2 c^2 lambda^3)/(h^2)` (d)`lambda_0 = lambda`

Electrons with de-Broglie wavelength lambda fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

Electrons with de-Broglie wavelength lambda fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

Electrons with de-Broglie wavelength lambda fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

Electrons with de-Broglie wavelength lambda fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

Eletrons with de- Broglie wavwlength lambda fall on the target in an X- rays tube . The cut off wavelength of the emitted X- rays is

Electrons of mass m with de - Broglie wavelength , lambda fall on the target in an X-ray tube . The cutoff wavelength (lambda_0) of the emitted X-ray is:

Two particle are moving perpendicular to each with de-Broglie wave length lambda_(1) and lambda_(2) . If they collide and stick then the de-Broglie wave length of system after collision is : (A) lambda = (lambda_(1) lambda_(2))/(sqrt(lambda_(1)^(2) + lambda_(2)^(2))) (B) lambda = (lambda_(1))/(sqrt(lambda_(1)^(2) + lambda_(2)^(2))) (C) lambda = (sqrt(lambda_(1)^(2) + lambda_(2)^(2)))/(lambda_(2)) (D) lambda = (lambda_(1) lambda_(2))/(sqrt(lambda_(1) + lambda_(2)))

Two particle are moving perpendicular to each with de-Broglie wave length lambda_(1) and lambda_(2) . If they collide and stick then the de-Broglie wave length of system after collision is : (A) lambda = (lambda_(1) lambda_(2))/(sqrt(lambda_(1)^(2) + lambda_(2)^(2))) (B) lambda = (lambda_(1))/(sqrt(lambda_(1)^(2) + lambda_(2)^(2))) (C) lambda = (sqrt(lambda_(1)^(2) + lambda_(2)^(2)))/(lambda_(2)) (D) lambda = (lambda_(1) lambda_(2))/(sqrt(lambda_(1) + lambda_(2)))

lambda ^ (3) -6 lambda ^ (2) -15 lambda-8 = 0