[" 2.The line "(x)/(a)-(y)/(b)=1" mects the "X" - axis at "P" .Find the equation of the line perpendicula to this "],[" line at "P]

The line x/a-y/b=1 meets the X-axis at P. Find the equation of the line perpendicular to this line at P.

The line (x)/(a)-(y)/(b) =1 cuts the x-axis at P. The equation of the line through P perpendicular to the given line is

The line x/a-y/b=1 cuts the x-axis at P. Find the equation of the line through p and perpendicular to the given line.

The line x/a-y/b=1 cuts the x-axis at P. The equation of the line through P and perpendicular to the given line is

the line (x)/(a)-(y)/(b)=1 cuts the x -axes at P .the equation of the line passes through point P and perpendicular to the line is:

Let the line (x)/(a)+(y)/(b)=1 cuts the x and y axes at A and B respectively.Now a line parallel to the given line cuts the coordinate axis at P and Q and points P and Q are joined to B and A respectively.The locus of intersection of the joning lines is

Find the equation of the line perpendicular to the line 3x+4y+6=0 and making intercept -4 on X-axis.