[" The equation of displacement of two waves are given as "y_(1)=10sin(3 pi t+(pi)/(3));y_(2)=5(sin3 pi t+sqrt(3)cos],[3 pi t" ).Then what is the ratio of their amplitudes "]

The equation of displacement of two waves are given as y_(1) = 10 sin( 3 pi t + (pi)/(3)) , y_(2) = 5 [ sin 3 pi t + sqrt(3) cos 3 pi t] Then what is the ratio of their amplitudes

The equation of displacement of two waves are given as y_(1) = 10 sin( 3 pi t + (pi)/(3)) , y_(2) = 5 [ sin 3 pi t + sqrt(3) cos 3 pi t] Then what is the ratio of their amplitudes

The equation of displacement of two waves are given as y_(1) = 10 sin( 3 pi t + (pi)/(3)) , y_(2) = 5 [ sin 3 pi t + sqrt(3) cos 3 pi t] Then what is the ratio of their amplitudes

The equation of displacement of two waves are given as y_(1) = 10 sin( 3 pi t + (pi)/(3)) , y_(2) = 5 [ sin 3 pi t + sqrt(3) cos 3 pi t] Then what is the ratio of their amplitudes

The equation of displacement of two waves are given as y_(1)=10sin(3 pi t+(pi)/(3)) , y_(2)=10sin(3 pi t+(pi)/(3)) .Then what is the ratio of their amplitudes

The equations of two SHM are y_(1)=10sin(4pit+pi/4),y_(2)=5(sin3pit+sqrt3cos3pit) . What is the ratio of their amplitudes?

Equations of two SHMs are y_(1)=10sin(3pit+pi/4)andy_(2)=5(sin3pit+sqrt3cos3pit) . Determine the ratio of their amplitudes.

The S.H.M.s of two particles are given by y_(1)=10 "sin" [2pi t +(pi)/(6)] " and " y_(2) =5["sin" 2pi t + sqrt(3) "cos" 2 pi t] The ratio of their amplitudes is