In the arrangement of figure assume negligible friction between the blocks and table. If F the pulling force and `m_(1)` and `m_(2)` the masses are known, then the tension in the string is–

In the arragement of figure assume negligible friction between the blocks and table. If F the pulling force and m_(1) and m_(2) the masses are known, then the tension in the string is :

In the arragement of figure assume negligible friction between the blocks and table. If F the pulling force and m_(1) and m_(2) the masses are known, then the tension in the string is :

If coeffiecient of friction between the block of mass 2kg and table is 0.4 then out acceleration of the system and tension in the string. (g=10m//s^(2))

If coeffiecient of friction between the block of mass 2kg and table is 0.4 then out acceleration of the system and tension in the string. (g=10m//s^(2))

If coeffiecient of friction between the block of mass 2kg and table is 0.4 then out acceleration of the system and tension in the string. (g=10m//s^(2))

In figure assume that there is nagligible friction between the blocks and table. Compute the tension in the cord connecting m_(2) and the pulley and acceleration of m_(2) if m_(1) = 300 g , m_(2) = 200 g and F = 0.40N

A block A of mass m_1 rests on a horizontal table . A light string connected to it passes over a frictionless pulley at the edge of table and from its other end another block B of mass m_2 is suspended . The coefficient of kinetic friction between the block and the table is mu . When the block A is sliding on the table the tension in the string is :

In the arrangement shown in figure , there is friction between the blocks of masses m and 2m which are in contact . The ground is smooth . The mass of the suspended block is m . The block of mass m which is kept on mass 2m is stationary with respect to block of mass 2 m . The force of friction between m and 2 m is (pulleys and string are lig frictionless ) :