A lens has a power of `+-` diopeters in air. What will be its power if completely immersed in water? `(._amu_(w)=4//3 and _amu_(g)=3//2)`

A lens has a power of +-5 diopeters in air. What will be its power if completely immersed in water? (._amu_(w)=4//3 and _amu_(g)=3//2)

A convex lens of power P is immersed in water. How will its power change ?

A lens has a power of +5 D in air.If completely immersed in water,what will be its power ?Given,refractive index of glass = 3//2 ,refractive index of water = 4//3 .

The power of a lens kept in air is P. When it is immersed in water, then power becomes ( mu _(water) =4/3, mu_(Lens) = 3/2 )

The power of a lens kept in air is P. When it is immersed in water, then power becomes ( mu _(water) =4/3, mu_(Lens) = 3/2 )

The foal length of a glass convex lens in air is 15 cm.Calculate its focal lenth,when is is totally immersed in wate.Given a^mu_w=4//3 and a^mu_g=1.5 .

Power of a lens is + 3 D. What will be the focal length of the lens?

A convex lens of glass has power P in air. If it is immersed in water its power will be