sqrt(25.3)

Using differentiable, find the approximate value of each of the following upto 3 places of decimal. sqrt25.3

Find the approximate value of sqrt25.3 using differentials.

Evaluate sqrt(-16)+3sqrt(-25)+sqrt(-36)-sqrt(-625)

The value of 1/(sqrt(3.25) + sqrt(2.25)) + 1/(sqrt(4.25) + sqrt(3.25))+ 1/(sqrt(5.25) + sqrt(4.25)) + 1/(sqrt(6.25) + sqrt(5.25)) is:

Rationalise the denominator of (2*3sqrt(3))/(3sqrt(25)) .

Prove that: ((64)/(125))^(-2/3)+1/(((256)/(625))^(1/4))+\ ((sqrt(25))/(root(3)64))=(65)/(16)

Simplify sqrt(25)/(64)^(1/3)+(256/625)^(-1/4)+1/(64/125)^(2/3)

Find the value of (9^(3//2)-3xx5^(0)-[(1)/(81)]^(-1//2))/(((64)/(125))^(-2//3)+(1)/(((256)/(625))^(1//4))+((sqrt(25))/(root(3)(64)))) .

Simplify: sqrt (-16) + 3 sqrt (-25) + sqrt (-36) + sqrt (-625)