Latus rectum of the parabola whose focus is (3, 4) and whose tangent at vertex has the equation `x + y = 7 + 5sqrt2` is

Let l be the length of the latus rectum of the parabola whose focus is (1,2) and two tangents are x-y=0 and x+y=0 , then l is equal to (sqrt5=2.24)

Consider the parabola whose focus is at (0,0) and tangent at vertex is x-y+1=0 The length of latus rectum is

Consider the parabola whose focus is at (0,0) and tangent at vertex is x-y+1=0 The length of latus rectum is

find the equation of parabola whose focus is (5,2) and vertex is at (3,2)

The length of latus rectum of parabola whose whose focus is (-6,6) and vertex is (-2,2) is

Length of latus rectum of a parabola whose focus is (3,3) and directrix is 3x - 4y - 2 = 0 is

The length of the latus rectum of the parabola whose focus is (3,3) and directrix is 3x-4y-2=0 is.

Find the length of the latus rectum of the parabola whose focus is at (2, 3) and directrix is the line x-4y+3=0 .

Find the length of the latus rectum of the parabola whose focus is at (2, 3) and directrix is the line x-4y+3=0 .

Find the length of the latus rectum of the parabola whose focus is at (2, 3) and directrix is the line x-4y+3=0 .