The length,radius and resistivity of two wires are each in the ratio 1:3. The resistance of the comparatively thin wire is `20 Omega`. Determine the resistance of the other wire.

The lengths radii and specific resistance of two conducting wires are each in the ratio of 1:3. If the resistance of the thinner wire is 10 Omega then the resistance of the other wire will be

Two wires are having length , resistivity and their radius in the ratio of 1:3 . Resistance of the thinner wire is 10 Omega , then the resistance of the other wire will be

for two different wires-the length, radius and resistivity are in the ratio 2 : 1 . If one of then has resistance of 10Omega , What will be the resistance of the other?

Length,diameter and specific resistance of two wires of different materials are each in the ratio 2:1 .One of the wires has a resistance of 10 ohm. Find the resistance of the other wire.

A wire of resistance 1Omega is elongated by 10%. The resistance of the elongated wire is

The lengths diameters and resistances of two wire are in the ratio of 1:2 Determine the ratio of the resistivities for their materials.

A wire of resistance 1 Omega is elongated by 10%. The resistance of the elongated wire is

The lengths,resistances and resistivities of materials of two wires-each is in the ratio of 1:2 What is the ratio between their diameters?