The base of a triangle is 80 and one of the base angles is `60^@`. IF the sum of the lengths of the other two sides is 90, then the shortest side is

The base of a triangle is 80 and one of base angle is 60^(@) . If the sum of the lenghts of he other two sides is 90. then the shortest side is

The base of a trianangles is 80 and one of the base angles is 60^(@) .If the sum of the lenghts of thewo sides is 90 ,then the shortest side is

The base of a triangle is 80cm and one of the base angles is 60^(@) .If the sum of the lenghts of the other two sides is 90cm,then the length of the shortest side is

The base of a triangle is 80cm and one of the base angles is 60^(@) .If the sum of the lenghts of the other two sides is 90cm,then the length of the shortest side is

If the base of a triangle and the ratio of the lengths of the other two unequal sides are given, then the vertex lies on

If the base of a triangle and the ratio of the lengths of the other two unequal sides are given, then the veterx lies on

If the base of a triangle and the ratio of the lengths of the other two unequal sides are given,then the vertex lies on

Theorem 6.9 : In a triangle, if square of one side is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle.

Prove that in a triangle if the square of one side is equal to the sum of the squares of the other two side then the angle opposite to the first side is a right angle.