Test if the following equations are dimensionally correct:
a` h=(2Scostheta)/(rhorg)` b. `nu= sqrt(P/rho),
c. `V=(pi P r^4t)/(8etal),`
d. `v=(1)/(2pi) sqrt(mgl)/(I)`
where h height, S= surface tension, `rho`= density, P= pressure, V=volume, `eta` = coefficient of viscosity, v= frequency and I = moment of inertia.

Test if the following equation is dimensionally correct: h= ((sS cos theta)/(r p g)) where h= height, S= surface tension, p= density, r=radius, and g= acceleration due to gravity.

Check whether the following relations are dimensionally correct : (a) V = (pi pr^(4))/(8 eta l) (b) h = (2 s)/(rho rg) (c ) T = 2 pi sqrt((I)/(MB)) (d) v = (E)/(B) Where V: volume, p: pressure, r: radius, eta: coefficient of viscosity, l: length, h: height, s: surface tension, rho: density, g: acceleration due to gravity, I: moment of inertia, M: magnetic moment, B: magnetic field, v: speed and E: electric field.

Check by the method of dimensions, whether the folllowing relation are dimensionally correct or not. (i) upsilon = sqrt(P//rho) , where upsilon is velocity. P is prerssure and rho is density. (ii) v= 2pisqrt((I)/(g)), where I is length, g is acceleration due to gravity and v is frequency.

Test if following equation is equation is dimensionally correct v=(1)/(2pi)sqrt((mgl)/(1)) where, v = frequency, I =moment of inertia, m= mass, l= lengh, g= acc. Due to gravity.

Check the accuracy of the relation eta= (pi)/(8)(Pr^4)/(lV) Here, P is pressure, V= rate of flow of liquid through a pipe, eta is coefficient of viscosity of liquid.

Check the correctness of the equation v=(K eta)/(r rho) using dimensional analysis, where v is the critical velocity eta is the coefficient of viscosity, r is the radius and rho is the density?

Check the correctness of the relation V=(pipr^(4))/(8etal) where V is the volume per unit time of a liquid flowing through a tube of radius r and length l, eta is the coefficient of viscosity of the liquid and p is the pressure difference between the ends of the tube.

The rate of flow of liquid in a tube of radius r, length l, whose ends are maintained at a pressure difference P is V = (piQPr^(4))/(etal) where eta is coefficient of the viscosity and Q is

The rate of flow of liquid ina tube of radius r, length l, whose ends are maintained at a pressure difference P is V = (piQPr^(4))/(etal) where eta is coefficient of the viscosity and Q is

The volume of a liquid flowing out per second of a pipe of length I and radius r is written by a student as V=(pi)/(8)(pr^(4))/(etal) where p is the pressure difference between the two ends of the pipe and eta is coefficent of viscosity of the liquid having dimensional formula (ML^(-1)T^(-1)) . Check whether the equation is dimensionally correct.