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If x^2-4x-1=0 then x^3-1/(x^3)=...

If `x^2-4x-1=0` then `x^3-1/(x^3)=`

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If (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) and x ne 1/3 then x=? यदि (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) है तथा x ne 1/3 है, तो x=?