The peak value of an alternating voltage applied to a `50 omega` resistance is 10V. Find the rms current. If the voltage frequency is 100 Hz, write the equation for the instantaneous current.

The peak value of an alternating voltage applied to a 50 Omega resistance is 10 V. Find the rms current. If the frequency of the applied voltage is 60 Hz, write the equation for the instantaneous current.

Find the rms value of current if the peak value of an alternating voltage applied to a 20 omega resistance is 8 V . Also write the equation for instantaneous current if the voltange frequency is 60 Hz.

An alternating voltage is represented by V = 240 sin 100 πt V. Find the peak voltage, rms voltage, frequency of the source.

A sinusoidal voltage v=200 sin 314 t is applied to a resistor of 10Omega resistance. Calculate the rms value of the voltage

When an alternating voltage of 100V, 50 Hz is applied to a choke coil, it takes a current of 10 A and the power is 500 W. What is the choke coil?

A alternating voltage varies with time (t) as V=100sin(50pit) . The rms voltage and the frequency respectively, are

The equation of an alternating voltage is V=100sin100πt volt. Find the RMS value of voltage and frequency.

An alternative voltage V=30 sin 50t+40cos 50t is applied to a resitor of resistance 10 Omega . Time rms value of current through resistor is

The equation of an alternating voltage is V =100sqrt2 sin 100pit volt. The RMS value of voltage and frequency will be respectively

A sinusoidal voltage of amplitude 5V is applied to resistance of 500 Omega . The r.m.s. current in the circuit is