[" If "beta" is one of the angles between the "],[" normels to the eflipse,"x^(2)+3y=9" at the "],[" points "(3cos theta,sqrt(3)sin theta)" and "],[3sin theta,sqrt(3)cos theta);theta in(0,(pi)/(2)):" then "(2cot beta)/(sin2 theta)]

cos theta+sqrt(3)sin theta=2

If beta is one of the angles between the normals to the ellipse, x^2+3y^2=9 at the points (3 cos theta, sqrt(3) sin theta)" and "(-3 sin theta, sqrt(3) cos theta), theta in (0,(pi)/(2)) , then (2 cot beta)/(sin 2 theta) is equal to:

If beta is one of the angles between the normals to the ellipse, x^2+3y^2=9 at the points (3 cos theta, sqrt(3) sin theta)" and "(-3 sin theta, sqrt(3) cos theta), theta in (0,(pi)/(2)) , then (2 cos beta)/(sin 2 theta) is equal to:

If sqrt(3) cos theta + sin theta = sqrt(2) , then theta =

(sin3 theta-sin theta)/(cos theta-cos3 theta)=cot2 theta

The distance between the points (cos theta,sin theta) and (sin theta-cos theta) is sqrt(3)(b)sqrt(2)(d)1

Solve sqrt(3) cos theta-3 sin theta =4 sin 2 theta cos 3 theta .

Solve sqrt(3) cos theta-3 sin theta =4 sin 2 theta cos 3 theta .