The resistance of an ammeter of range 5A is `1.8Omega` A shunt of `0.2Omega` is connected in parallel to it. When its indicator shows a current of 2A then what will be effective current?

The resistance of a galvanometer is 100Omega . A shunt of 5 Omega is connected to it to convert it into an ammeter. The internal resistance of the ammeter is

The resistance of galvanometer is 999 Omega . A shunt of 1Omega is connected to it. If the main current is 10^(-2)A , what is the current flowing through the galvanometer.

The resistance of galvanometer is 999Omega . A shunt of 1 Omega is connected to it.If the main current current is 10^(-2)A , what is the current flowing through the galvanometer .

The resistance of an ammeter having a range of 0 to 5 A is 1.8 Omega . It is shunted by a small resistance of 0.2 Omega . If the original dial and the scale indicating the current is not changed, then the effective current when its pointer indictaes 1.5 A will be

A shunt of 1 Omega is connected in parallel with a galvanometer of resistance 99 Omega . IF the main current of the circuit be 1A, then what will be the galvanometer current?