" (x) "(a)/(x-a)+(b)/(x-b)=(2c)/(x-c),x!=a,b,c

Long-answer type questions (L.A.) (a)/(x-a)+(b)/(x-b)=(2c)/(x-c)(xnea,b,c) .

Find x in terms of a , b and c : (a)/(x - a) + (b)/(x - b) = (2 c)/(x - c) , x - a , b , c

Find x in terms of a,b and c(a)/(x-a)+(b)/(x-b)+(c)/(x-c)=2(c)/(x-c)x!=a,x!=b,x!=c

Solve by factorization: (a)/(x-a)+(b)/(x-b)=(2c)/(x-c)

Solve by factorization: a/(x-a)+b/(x-b)=(2c)/(x-c)

If (x^(3))/((x-a)(x-b)(x-c))=1 +(A)/(x-a)+(B)/(x-b)+(C)/(x-c) then A=

(x^(3))/((x-a)(x-b)(x-c))=1+(A)/(x-a)+(B)/(x-b)+(C)/(x-c) then A=

If (x^(3))/((x-a)(x-b)(x-c))=1 +(A)/(x-a)+(B)/(x-b)+(C)/(x-c) then A=

If |(1,1,1),(a,b,c),(a^(3),b^(3),c^(3))| = (a - b) (b - c) (c - a) (a + b + c) , where a,b,c are all different, then the determinant |(1,1,1),((x-a)^(2),(x-b)^(2),(x-c)^(2)),((x-b)(x-c),(x-c)(x-a),(x-a)(x-b))| vanishes when a)a + b + c = 0 b) x = (1)/(3) (a + b + c) c) x = (1)/(2) (a + b + c) d) x = a + b + c