[" Yrom a circular sheet of radius "4cm," a circle of radius "3cm" is removed.Find the area "],[" of the remaining sheet.(Take "pi=3.14" ) "]

From a circular sheet of radius 4cm, a circle of radius 3cm is removed. Find the area of the remaining sheet. (Take pi=3.14 )

From a circular sheet of radius 4 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet. (Takepi = 3.14)

6).From a circular sheet of radius 4 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet. (take pi=22/7) (7).Saima wants to put a lace on the edge of a circular table cover of diameter 1.5 m. Find the length of the lace required and also find its cost if one meter of the lace costs ?15.(take pi=22/7)

6).From a circular sheet of radius 4 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet. (take pi=22/7 )(7).Saima wants to put a lace on the edge of a circular table cover of diameter 1.5 m. Find thelength of the lace required and also find its cost if one meter of the lace costs ₹15.(take pi=22/7 )

From a circular aluminium sheet of radius 14 cm, a sector of angle 45^(@) is removed. Find the percentage of the area of the sector removed.

The side of a square metal sheet is 14 cm. A circular sheet of greatest diameter is cut out from it and removed. Find the area of the remaining metal sheet. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Area of circular sheet =pir^(2)=(22)/(7)xx7xx7=154cm^(2) Area of square metal sheet = ("side")^(2)=(14)^(2)=196cm^(2) (B) Since the circular sheet has greatest diameter, diameter of the circle = side of the square = 14 cm. (C) therefore "Radius of the circle sjeet"=(14)/(2)=7cm (D) therefore "The area of the remaining metal sheet"="Area of the square metal sheet"-"Area of the circular sheet"=196-154=42cm^(2)