" प्रशन 8."(x)/((x-1)^(2)(x+2))

If int(x^(2)+1)/((x-1)^(2)(x+3))dx=(3)/(8)log|x-1|-(1)/(2(x-1))+F(x)+C then 8F'(2) equals to

(x)/(2)+(x)/(8)=(1)/(8)

(x-2)^(2),(x-1)^(2),x^(2)(x-1)^(2),x^(2),(x+1)^(2)x^(2),(x+1)^(2),(x+2)^(2)]|=-8

underset(x to 1//2)lim {(8x-3)/(2x-1)-(4x^(2)+1)/(4x^(2)-1)}=

lim_(x to 1/2)((8x-3)/(2x-1)-(4x^(2)+1)/(4x^(2)-1)) .

int (x+1)(x+2)^(7)(x+3)dx is equal to a) ((x+2)^(10))/(10) - ((x+2)^(8))/(8) + c b) ((x+1)^(2))/(2) - ((x+2)^(8))/(8) - ((x+3)^(2))/(2) + c c) ((x+2)^(10))/(10) + c d) ((x+1)^(2))/(2) + ((x+2)^(8))/(8) + ((x+3)^(2))/(2) + c

The expression (1)/(x-1)-(1)/(x+1)-(2)/(x^(2)+1)-(4)/(x^(4)+1) is equal to (8)/(x^(8)+1)( b) (8)/(x^(8)-1)( c) (8)/(x^(7)-1) (d) (8)/(x^(7)+1)

Factorise : (x^(2)-1)^(2)+8x(x^(2)+1)+19x^(2)