If `x=a(2theta-sin2theta)` and `y=a(1-cos2theta)` find `(dy)/(dx)` when `theta = pi/3`

If x=a(2 theta-sin2 theta) and y=a(1-cos2 theta) find (dy)/(dx) when theta=(pi)/(3)

If x=a (theta-sin theta) and y=a(1-cos theta) , find (d^(2)y)/(dx^(2)) at theta=pi.

If x=a(theta-sin theta) and,y=a(1+cos theta) find (dy)/(dx) at theta=(pi)/(3)

If [x= a{theta - sin(theta)] and [y= a{1 - cos (theta)] find [d^2y/dx^2 at (theta = pi/2)

x=a(theta-sin theta), y= a (1+cos theta) find (dy)/dx "at " " " theta=pi/2 .

If x = a (theta + sin theta), y = b (1+ cos theta), then (dy)/(dx)" at "theta = (pi)/(2) is:

If x=cos theta-cos 2theta and y=sin theta-sin2theta , then find (dy)/(dx) .

If x=a(cos theta+log tan((theta)/(2))) and y=a sin theta then find (dy)/(dx) at theta=(pi)/(3) and theta=(pi)/(4)