If we reduce 3x+3y+7=0 to the form xcosa...

If we reduce `3x+3y+7=0` to the form `xcosalpha+ysinalpha=p ,` then the value of `p` is `7/(2sqrt(3))` (b) `7/3` (c) `(3sqrt(7))/2` (d) `7/(3sqrt(2))`

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If we reduce 3x+3y+7=0 to the form xcosalpha+ysinalpha=p , then find the value of p .

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If we reduce 3x+3y+7=0 to the form x cos alpha+y sin alpha=p, then the value of p is (7)/(2sqrt(3))( b) (7)/(3)( c) (3sqrt(7))/(2)( d) (7)/(3sqrt(2))

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Find the value of a and b if (7+3sqrt(5))/(3+sqrt(5))-(7-3sqrt(5))/(3-sqrt(5)) =a + bsqrt(5)