Home
Class 10
MATHS
क्या x = 3 निम्न समीकरण का मूल है? sqr...

क्या `x = 3` निम्न समीकरण का मूल है?
`sqrt(x^(2)-4x+3)+sqrt(x^(2)-9)=sqrt(4x^(2)-14x+16)`

Promotional Banner

Similar Questions

Explore conceptually related problems

(4) sqrt(3)x^(2)+2x-sqrt(3)=0

The number of real solutions of sqrt(x^(2)-4x+3)+sqrt(x^(2)-9)=sqrt(4x^(2)-14x+6)

Solve: sqrt(x^2-16)-sqrt(x^2-8x+16)=sqrt(x^2-5x+4) .

The Range of sqrt(-x^(2))+sqrt(x^(2)-4x+9) is

The number of real solutions of sqrt(x^2-4x+3)+sqrt(x^2-9)=sqrt(4x^2-14x+6)

The number of real solutions of sqrt(x^2-4x+3)+sqrt(x^2-9)=sqrt(4x^2-14x+6)

The number of real solutions of sqrt(x^2-4x+3)+sqrt(x^2-9)=sqrt(4x^2-14x+6)

The number of real solutions of sqrt(x^2-4x+3)+sqrt(x^2-9)=sqrt(4x^2-14x+6)

lim_(x to oo ) (sqrt(3x^(2)-1)-sqrt(2x^(2)-3))/(4x+3)

lim_(x to oo ) (sqrt(3x^(2)-1)-sqrt(2x^(2)-3))/(4x+3)