(3x+1)/((x-1) (x+3)) = (A)/(x-1) + (B)/(...

`(3x+1)/((x-1) (x+3)) = (A)/(x-1) + (B)/(x+3)` तब `"sin"^(-1) (A)/(B)=`

`pi//4`

`pi//2`

`pi//3`

`pi//6`

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