`NH_(4)OH` की सीमान्त मोलर चालकता `(Lambda_(m)^(0)(NH_(4)OH)` निम्न में से जिसके बराबर है, वह है -

Options

A. `Lambda_(m(NH_4OH))^@ + Lambda_(m(NH_4Cl))^@ - Lambda_(m(HCl))^@`
B. `Lambda_(m^@(NH_4Cl)) + Lambda_(m(NaCl))^@ - Lambda_(m(NaCl))^@`
C. `Lambda_(m(NH_4Cl))^@ + Lambda_(m(NaCl))^@ - Lambda_(m(NaOH))^@`
D. `Lambda_(m(NaOH))^@ + Lambda_(m(NaCl))^@ - Lambda_(m(NH_4Cl))^@`

Answer

B

Explanation

`Lambda_(m(NH_4Cl))^@ + Lambda_(m(NaOH))^@ - Lambda_(m(NaCl))^@`
`Lambda_(m(NH_4^(+)))^@ + Lambda_(m(Cl^(-)))^@ +Lambda_(m(Na^(+)))^@ + Lambda_(m(OH^(-)))^@- Lambda_(m(Na^(+)))^@ - Lambda_(m(Na^(+)))^@ - Lambda_(m(Cl^(-)))^@`
`=Lambda_(m(NH_4^(+)))^@ + Lambda_(m(OH^(-)))^@ = Lambda_(m(NH_4OH))^@`