A wire of cross -sectional area `4 xx 10^(-4) m^(2)` , modulus of elasticity `2 xx 10^(11) Nm^(-2)` and length 1 m is stretched between two rigid poles . A mass of 1 kg is suspended at its middle . Calculate the angle it makes with horizontal . Take g = `10 ms^(-2)`

A mild steel wire of length 1.0 m and cross-sectional are 0.5 xx 10^(-2)cm^(2) is streached, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid point of the wire, calculate the depression at the mid point. g = 10ms^(-2), Y=20 xx 10^(11)Nm^(-2 .

A mild steel wire of length 1.0 m and cross-sectional are 0.5 xx 10^(-20)cm^(2) is streached, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid point of the wire, calculate the depression at the mid point. g = 10ms^(-2), Y=2 xx 10^(11)Nm^(-2 .

A wire of length 2m and cross-sectional area 2 xx 10^(-6) m^(2) is made of a material of Young's modulus 2 xx 10^(11) Nm^(-2) . What is the work done in stretching it through 0.1 mm.

A mild steel wire of length 1.0m and cross sectional area 5.0xx10^(-2)cm^(2) is stretched, within its elastic limit horizontally between two pillars. A mass of 100g is suspended form the midpont of the wire. Calculate the depression at the midpoint (Y_("steel) = 200GPa)

A mild steel wire of length 1.0 m and cross sectional area 0.50 xx 10 ^(-2) cm^(2) is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.

A mild steel wire of length 1.0 m and cross - sectional area 0.50xx10^(-2)" cm"^(2) is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid - point of the wire. Calculate the depression at the mid point.