In a cross in Drosophila , the heterozygous member with grey body `(b^(+))` and long wings `(vg^(+))` was crossed with had the following ratio grey vestigial 24 : grey long 126: black long 26 : black vestigial 124 . What is the frequency of recombinant in the population ?

In a cross in Drosophila , the heterozygous member with grey body (b^(+)) and long wings (vg^(+)) was crossed with black body (b) and vestigial wing (vg) and had the following ratio grey vestigial 24 : grey long 126: black long 26 : black vestigial 124 . What is the frequency of recombinant in the population ?

Answer the following questions referring the data below. Grey colour (b^(+)//b) , normal winged (Vg^(+)//Vg) F_1 female X Black coloured (b/b) vestigial winged (Vg/Vg) male. The offspring were grey normal 126, grey vestigial 24, black normal 26 and black vestigial 124. What is the cause of above phenotypic ratio?

Answer the following questions referring the data below. Grey colour (b^(+)//b) , normal winged (Vg^(+)//Vg) F_1 female X Black coloured (b/b) vestigial winged (Vg/Vg) male. The offspring were grey normal 126, grey vestigial 24, black normal 26 and black vestigial 124. What ratio is expected in this cross? Does the above phenotypic ratio confirm the expected ratio?

In a diploid population of Drosophila 9% of the population is black in colour. Black is recessive to grey. What is the frequency of heterozygous flies in that population, if it is in Hardy-Weinberg equilibrium?

In a diploid population of Drosophila 9% of the population is black in colour. Black is recessive to grey. What is the frequency of heterozygous flies in that population, if it is in Hardy-Weinberg equilibrium?

Let us do the following activity to understand the mendelian principles of heredity. Materaials required: a. 3cm length and 1 cm breadth chart pieces -4 b. 2 cm length and 1 cm breadth chart pieces -4 c. Red byuttons -4 d. white buttons -4 e. chart, scale, sketch pen penil, 2 bags. Method: Prepare a chart with 2x2 boxes along with numbe and symbol as shown in the figure. Game 1: Monohybrid cross (starting with hybrid parents) To start with take 1,2 or 3,4 . In case you start 1,2 pik all the 16 log and short pieces and prepare such paris in each of which you have a long and short piece. Take 4 pairs each of long and short strips and put them in two separate bags. Now each bag contains 8 strips (4 long and 4short). One bag say 'A' represents mael and the bag 'B' represents female . Now rendomly pick one strip each from bag A and B and put them together in the 1 on the chart. Keep picking out the strips and arrange them in the same manner till your bags are empty. Same time your boxes in the chart are filled with paris of strips. you might have got the following combinations, two long strips, one long and one short strip, two short strips. (Q) D. What is the percentage of each type? also find their ratios.

In fruits flies, long wing is dominant to vestigial wing. When heterozygous long-winged flies were crossed with vestigial-winged flies, 192 offsprings were produced. If an exact Mendelian ratio had been obtained, then the number of each phenotype would have been

In fruits flies, long wing is dominant to vestigial wing. When heterozygous long-winged flies were crossed with vestigial-winged flies, 192 offsprings were produced. If an exact Mendelian ratio had been obtained, then the number of each phenotype would have been