`25=(ky-1)^2`
In the equation above y=-2 is one solution. If K is a constant, what is a possible value of k?

{((3)/(4)x-(1)/(2)y=12), (kx-2y=22):} If the system of linear equations above has no solution, and k is a constant, what is the value of k?

11x-24y=8 kx-36y=5 In the system of equations above, k is a constant. If the system has no solutions, what is the value of k?

(1)/(2)x-(5)/(6)y=5 -2x+ky=3 In the system of linear equations above, k is a constant. If the system has no solution, what is the value of k?

(k-1)x+(1)/(3)y=4 k(x+2y)=7 In the system of linear equations above, k is a constant. If the system has no system, what is the value of k?

(3)/(2)x-(1)/(2)y=7 kx-6y=4 In the system of linear equation above, is a constant. If the system has no solution, what is the value of k?

(y^(2)+ky-3)(y-4)=y^(3)+by^(2)+5y+12 In the equation above, k is a nonzero constant. If the equation is true for all values of y, what is the value of k?

sqrt(k=2)-x=0 Is the equation above, k is a constant . IF x=9 what is the value of k?

If (2, 5) is a solution of 3x+ky=31 , what is the value of k?

kx-3y=4 4x- 5y =7 In the system of equations above, k is a constant and x and y are variables. For what value of k will the system of equations have no solution?