A long narrow horizontal slit lies `1 mm` above a plane mirror. The interference pattern produced by the slit and its and its image is viewed on a screen `sum` distance `1m` from the slit. The wavelength of light is `600 nm`. Then the distance of the first maxima above the mirror is equal to `(d lt lt D)` :

A long narrow horizontal slit lies 1mm above a plane mirror.The interference pattern produced by the slit and its image is viewed on a screen distant 1m from the slit .The wavelength of light is 600nm .Find the distance of first maximum above the mirror.

A long narrow horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1.0 m away from the slit, Find the fringe-width if the light used has a wavelength of 700 nm.

A long narrow horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1.0 in away from the slit, Find the fringe-width if the light used has a wavelength of 700 nm.

A long horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and the after reflection is seen on a screen 1 m away from the slit. If the mirror reflects only 64% of the light falling on it, the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is

A long horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and the after reflection is seen on a screen 1 m away from the slit. If the mirror reflects only 64% of the light falling on it, the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is

In a YDSE, distance between the slits and the screen is 1m, separation between the slits is 1mm and the wavelength of the light used is 5000nm . The distance of 100^(th) maxima from the central maxima is:

In a YDSE, distance between the slits and the screen is 1m, separation between the slits is 1mm and the wavelength of the light used is 5000nm . The distance of 100^(th) maxima from the central maxima is:

In a biprism experiment d=1mm. Interference fringes of width X=2.25 mm are observed on a screen at a distance of 3 m from the plane of the slit. The wavelength of incident light lies in the ____region.

In a Lloyds's mirror experiment as narrow slit S transmitting a light of wavelength lambda is placed 3 mm above a small plane mirror ( as shown). The light coming directly from the the slit and that coming after the reflection interfere on a screen placed at a distance of 90 cm from the slit. Length of mirror is 2 mm and the middle point of mirror is 2 mm from point P. If the mirror is shifted towards left then how does the fringe pattern on screen changes ?

In a Young's double slit experiment, the slit separation is 1mm and the screen is 1m from the slit. For a monochromatic light of wavelength 500nm , the distance of 3rd minima from the central maxima is