P & Q are the points with eccentric angles `theta`&`theta+pi/6`on the elipse `x^2/16 + y^2/4 =1`,then area of triangle OPQ is

If P and Q are points with eccentric angles theta and (theta+(pi)/(6)) on the ellipse (x^(2))/(16)+(y^(2))/(4)=1 , then the area (in sq. units) of the triangle OPQ (where O is the origin) is equal to

The points P Q R with eccentric angles theta, theta+alpha, theta+2 alpha are taken on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 then if area of triangle PQR is maximum then alpha =

The equation of the tangent at a point theta=3pi//4 to the ellipse x^(2)//16+y^(2)//9=1 is

if P,Q are two points on the line 3x+4y+15=0 such that OP=OQ=9 then the area of triangle OPQ is

if P,Q are two points on the line 3x+4y+15=0 such that OP=OQ=9 then the area of triangle OPQ is

if P,Q are two points on the line 3x+4y+15=0 such that OP=OQ=9 then the area of triangle OPQ is

if P,Q are two points on the line 3x+4y+15=0 such that OP=OQ=9 then the area of triangle OPQ is

Area of the parallelogram formed by the tangents at the points whose eccentric angles are theta,theta+((pi)/(2)),theta+pi,theta+((3 pi)/(2)) on the ellipse 16x^(2)+25y^(2)=400 is

The area of the parallelogram formed by the tangents at the points whose eccentric angles are theta, theta + pi/2, theta + pi, theta +(3pi)/2 on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is

The area of the parallelogram formed by the tangents at the points whose eccentric angles are theta, theta +(pi)/(2), theta +pi, theta +(3pi)/(2) on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2)) =1 is