हल कीजिए `(dy)/(dx)+ 2ytan x = sin x, y = 0` जब `x = pi/3`

(dy)/(dx) + 2 y tan x = sin x, y = 0 when x = (pi)/(3) .

dy/dx - ytan x = - 2 sin x

(dy)/(dx) = 3y cot x = sin 2x, y = 2 when x = (pi)/(2)

(dy)/(dx) - 3y cot x = sin 2x, y = 2 when x = (pi)/(2)

(dy)/(dx) = 3y cot x = sin 2x, y = 2 when x = (pi)/(2)

Find particular solution of differential equation (dy)/( dx) + 2y tan x = sin x , y =0 , when x = (pi)/(3) .

The solution of (dy)/(dx) + 2y tan x = sin x , given that y = 0, x =(pi)/(3) is

dy/dx - 3y cot x = sin 2x, given y= 2 when x = pi/ 2