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(tantheta)/(sectheta-1)+(tantheta)/(sect...

`(tantheta)/(sectheta-1)+(tantheta)/(sectheta+1)` is equal to `2tantheta` (b) `2sectheta` (c) `2\ cos e c\ theta` (d) `2\ t a nthetasectheta`

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(tantheta)/(sectheta-1)+(tantheta)/(sectheta+1) is equal to (a) 2tantheta (b) 2sectheta (c) 2\ cos e c\ theta (d) 2\ t a nthetasectheta

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