Home
Class 12
CHEMISTRY
Given the standard half - cell potential...

Given the standard half - cell potentials `(E^(@))` of the following as :
`Zn rarr Zn^(2+)+2e , E^(@)=+0.76V`
`Fe rarr Fe^(2+)+2e, E^(@)=0.41V`
The the standard EMF of the cell with the reaction
`Fe^(2+)+Zn rarr Zn^(2+)+Fe` is -

Promotional Banner

Similar Questions

Explore conceptually related problems

Electrode potential for the following half-cell reactions are Zn rarr Zn^(2+)+2e^(-), E^(@)=+0.76V, Fe rarr Fe^(2+)+2e^(-), E^(@)=+0.44V The EMF for the cell reaction Fe^(2+)+Zn rarr Zn^(2+)+Fe will be

The standard potential E^(@) for the half reactions are as : Zn rarr Zn^(2+) + 2e^(-), E^(@) = 0.76V Cu rarr Cu^(2+) +2e^(-) , E^(@) = -0.34 V The standard cell voltage for the cell reaction is ? Zn +Cu^(2) rarr Zn ^(2+) +Cu

The standard potential E^(@) for the half reactions are as : Zn rarr Zn^(2+) + 2e^(-), E^(@) = 0.76V Cu rarr Cu^(2+) +2e^(-) , E^(@) = -0.34 V The standard cell voltage for the cell reaction is ? Zn +Cu^(2) rarr Zn ^(2+) +Cu

The standard reduction potential E^(@) for the half reactions are as : E^(@) Znrightarrow Zn^2+),E^(@) = +0.76V Fe rightarrow Fe^(2+)+ 2e^(-), E^(@) = 0.41V , The emf for the cell reaction, Fe^(2+)+ZnrightarrowZn^(2+) + Fe is ,

The standard oxidation potentials, E^(@) , for the half reactions are as, Zn rarr Zn^(2+) + 2e^(-), " " E^(@) = + 0.76 volt Fe rarr Fe^(2+) + 2e^(-), " " E^(@) = +0.41 volt The emf of the cell, Fe^(2+) + Zn rarr Zn^(2+) + Fe is:

The standard reductino potentials E^(c-) for the half reactinos are as follows : ZnrarrZn^(2+)+2e^(-)" "E^(c-)=+0.76V FerarrFe^(2+)+2e^(-) " "E^(c-)=0.41V The EMF for the cell reaction Fe^(2+)+Znrarr Zn^(2+)+Fe is

The standard reductino potentials E^(c-) for the half reactinos are as follows : ZnrarrZn^(2+)+2e^(-)" "E^(c-)=+0.76V FerarrFe^(2+)+2e^(-) " "E^(c-)=0.41V The EMF for the cell reaction Fe^(2+)+Znrarr Zn^(2+)+Fe is

The standard potential (E^(0)) for the half reaction are as Zn to Zn^(2+) + 2e^(-) , E^(0) = + 0.76 V Fe to Fe^(2+) + 2e^(-) , E^(0) = + 0.41 V . The emf for the cell reaction Fe^(2+) + Zn to Zn^(2+) + Fe is