The displacement of a particle performing S.H.M is `x=A" "sin(omegat+prop)`. The quantity `prop` is called

Kinetic energy of a particle performing S.H.M.

The amplitude of particle performing S.H.M. is

Kinetic energy of the particle performing S.H.M. is

The displacement of a particle performing S.H.M. is given by x=10 "sin"(omega t+ alpha) metre. If the displacement of the particle is 5m, then the phase of S.H.M. is

The displacement of a particle performing S.H.M. is x = 3 sin (314 t) + 4 cos (314 t). Then the initial phase angle is,

The equation of displacement of a particle performing a S.H.M. is x=0.25 "sin" (200 t) metre. What is the maximum velocity of the particle ?

The displacement of a particle performing S.H.M. is, x = 3 sin (314t) + 4 cos (314t), where x and t are in CGS units. Then the amplitude of the S.H.M. is,

The displacement of a particle performing S.H.M. is x = 0.1 sin (5pit)+0.4cos(5pit)m . Then the speed of the particle at 0.1 s will be