`A_((alpha))=[{:(cos alpha,-sin alpha),(sin alpha,cos alpha):}],A_((beta))=[{:(cos beta,-sin beta),(sin beta,cos beta):}]`
Which one of the following is correct ?

If A = [(cos alpha, sin alpha),(sin alpha, cos alpha)] and B = [(cos beta, sin beta),(sin beta, cos beta)] show that AB = BA

If f(alpha,beta)=|(cos alpha,-sin alpha,1),(sin alpha,cos alpha,1),(cos(alpha+beta),-sin(alpha+beta),1)|, then

If f(alpha,beta)=|(cos alpha,-sin alpha,1),(sin alpha,cos alpha,1),(cos(alpha+beta),-sin(alpha+beta),1)|, then

A_(alpha )= [(cos alpha, sin alpha),(- sin alpha, cos alpha)] then prove that A_(alpha . A_(beta) = A_(alpha + beta)

|(cos (alpha+beta),-sin (alpha+beta),cos 2 beta),(sin alpha, cos alpha, sin beta),(-cos alpha, sin alpha, cos beta)| is independent of

A = [[0, sin alpha, sin alpha sin beta-sin alpha, 0, cos alpha cos beta-sin alpha sin beta, -cos alpha cos beta, 0]]

[(cos alpha-cos beta)+i(sin alpha-sinbeta)]^n+[(cos alpha-cos beta)-i(sin alpha-sin beta)]^n=

If A=[(cos^(2)alpha, cos alpha sin alpha),(cos alpha sin alpha, sin^(2)alpha)] and B=[(cos^(2)betas,cos beta sin beta),(cos beta sin beta, sin^(2) beta)] are two matrices such that the product AB is null matrix, then alpha-beta is

If A=[(cos^(2) alpha, cos alpha sin alpha),(cos alpha sin alpha,sin^(2)alpha)] and B=[(cos^(2) beta, cos beta sin beta),(cos beta sin beta, sin^(2) beta)] are two matrices such that the product AB is the null matrix then alpha-beta is