The equation of simple Harmonic Oscillator having period `pi` s is given by `v=omega sqrt(100-x^(2))` where x is in metres and v is in `ms^(-1)` .The amplitude is

The equation of a simple harmonic wave is given by Y = 5sin""pi/2(100t - x) , where x and y are in metre and time is in second. The time period of the wave (m seconds) will be

The equation of a simple harmonic oscillator with amplitude 5 cm and period 2 sec is if particle is starting from the mean positions is–

The displacement of a particle executing simple harmonic motion is given by x=3sin(2pit+(pi)/(4)) where x is in metres and t is in seconds. The amplitude and maximum speed of the particle is

The ratio of the amplitudes of the simple harmonic oscillations given by y_1=Asinomegat and

The equation of progressive wave is given by y=10sin[300pi(t-(x)/(480))] where x and y are in metre and t is in second. Calculate the amplitude frequency time period and wavelength of the wave.

The displacement equation of a simple harmonic oscillator is given by y=A sin omegat-Bcos omegat The amplitude of the oscillator will be

The equation of displacement of a harmonic oscillator is x = 3sin omega t +4 cos omega t amplitude is