The solubility product of AgBr is `5.2times10^(-13)``g dm^(-3)` ,Calculate its solubility in `mol dm ^(-3)` .(Molar mass of AgBr=187.8g `mol ^(-1)`

The solubility product of AgBr is 5.2times10^(-13) moldm^-3 .Calculate its solubility in gdm^(-3) .(Molar mass of AgBr=187.8gmol^(-1) )

The solubility product of BaCl_2 is 4.0 xx 10 ^(–8) what will be its molar solubility in mol dm ^-3

The solubility of AgBr in water is 1.20 xx 10-5 mol dm ^-3 . Calculate the solubility product of Ag Br.

The solubility product of BaCl_(2) is 3.2xx10^(-9) . What will be solubility in mol L^(-1)

The solubility of silver bromide is 7.7 xx 10^(-13) mol^(2) L^(-2). Calculate the solubility of the salt.

A sparingly soluble salt gets precipitated only when the product of concentration of its ions in the solution (Q_(sp)) becomes greater than its solubility product. If the solubility of BaSO_(4) in water is 8 xx 10^(-4) mol dm^(-3) . Calculate its solubility in 0.01 mol dm^(-3) of H_(2)SO_(4) . Express your answer in scientific notation x xx 10^(-y) . Write the value of y.

If the solubility product of MOH is 1xx10^(-10) mol^(2) dm^(-6) then pH of its aqueous solution will be