`int_(0)^(pi) sqrt(1+4 "sin"^(2) x/2-4 "sin"x/2) dx` का मान कीजिए।

int_(0)^(pi//6) sqrt(1-sin 2x) dx

int_(0)^(pi//6) sqrt(1-sin 2x) dx

int_(0)^(2pi)sqrt(1+"sin"x/2)dx=

int_(0)^(2pi)sqrt(1+"sin"x/2)dx=

The integral int_(0)^(pi) sqrt(1 + 4 sin^2 x/2 - 4 sin x/2) dx equals :

int_(0)^((pi)/(4))sqrt(1+sin2x)dx

int_(0)^( pi)sqrt(1+4sin^(2)((x)/(2))-2sin((x)/(2)))dx

int_(0)^((pi)/(4)) sqrt(1+sin 2x) dx =

The integral int_(0)^(pi)sqrt(1+4"sin"^2(x)/(2)-4"sin"(x)/(2)) dx is equal to

The integral int_(0)^(pi)sqrt(1+4"sin"^(2)x/2-4"sin"x/2)dx is equals to (a) pi-4 (b) (2pi)/3-4-sqrt(3) (c) (2pi)/3-4-sqrt(3) (d) 4sqrt(3)-4-(pi)/3