An iron metre rod is allowed an error of 1 part per milliion. If the coefficient of linear expansion of ironis `1xx10^(-5).^(@)C^(-1)`, what is the maximum variation in temperature that the rod could have?

The coefficient of linear expansion of a metal rod is 12 xx 10^(-6//0)C , its value in per ^(0)F

An iron metal rod is to maintain an accuracy of one part per million. The coefficient of linear expansion of iron is 1 xx 10^(-5 //@)C respectively. The difference in lengths is 10cm at all temperatures. Their initital lengths must be respectively.

Coefficient of areal expansion of a solid is 2xx10^(-5).^(@)C^(-1) . Calculate its coefficient of linear expansion.

Coefficient of areal expansion of a solid is 2xx10^(-5).^(@)C^(-1) . Calculate its coefficient of linear expansion.

An iron rod and another of brass, both at 27^@C differ in length by 10^-3 m. The coefficient of linear expansion for iron is 1.1xx10^(-5)//^(@)C and for brass is 1.9xx10^(-5)//^(@)C . The temperature at which both these rods will have the same length is

An iron rod and another of brass, both at 27^@C differ in length by 10^-3 m. The coefficient of linear expansion for iron is 1.1xx10^(-5)//^(@)C and for brass is 1.9xx10^(-5)//^(@)C . The temperature at which both these rods will have the same length is

The length of a brass rod is 1.5 m. Its coefficient of linear expansion is 19xx10^(-6)K^(-1) Find the increase in length of the rod if it is heated through 20^(@)C .

The length of a zinc rod, when heated from 20^(@)C " to " 80^(@)C , increase by 0.6 cm. If the coefficient of linear expansion of zinc is 27 times 10^(-6@)C^(-1) , what is the initial length of the rod?

At temperature T, length of rod is L. If coefficient linear expansion of material of rod is 2 xx 10^(-2)//.^(@)C then length of rod when temperature of rod increased by 25^(@)C is