`A` and `B` are two points on uniform metal ring whose centre is `O` The angle `AOB =theta` A and `B` are maintaind at two different constant temperatures When `theta =180^(@)` the rate of total heat flow from `A` to `B` is `1.2W` When `theta =90^(@)` this rate will be .

A and B are two points on a uniform metal ring whose centre is C. The angle ACB=theta . A and B are maintained at two different constant temperatures. When theta=180^(0) , the rate of total heat flow from A to B is 1.2 W. When theta=90^(0) , this rate will be

A uniform metal ring with centre C have two points A and B such that angle ACB is theta . A and B are maintained at two different constant temperature. If the angle between A and B i.e. theta=180^(@) the rate of heat flow from A and B is 1.2W , then what will be the rate, when theta=90^(@) ?

If A and B are two points of a circle of radius r with centre at the point O and angleAOB = theta (in radians) then the area of the sector AOB is

A and B are two points on a uniform ring of resistance R the /_ASCB=theta , whre C is the centre of the sign. The equivalent reisrtance between A and b

Two conducting rods when connected between two points at constant but different temperatures separately, the rate of heat flow through them is q_1 and q_2 .