A flywheel is making `(3000)/(pi)` revolutions per minute about its axis. If the moment of inertia of the flywheel about that axis is 400 `kgm^(2)`, its rotational kinetic energy is :

A wheel is rotating about a its own axis. The moment of inertia of the wheel about axis of rotation.If its angular speed is 30 rad/sec and its kinetic energy is 300J ( in kg-m^(2))

The angular speed of a flywheel making 360 revolutions per minute is

A wheel is rotating at the rate of 10 revolutions per second about an axis about which the radius of gyration is 0.2m. If the mass of the wheel is 5 kg then its rotational kinetic energy is

A wheel is rotating at the rate of 10 revolutions per second about an axis about which the radius of gyration is 0.2m. If the mass of the wheel is 5 kg then its rotational kinetic energy is

The moment of Inertia of a particle about an axis of rotation is 0.2kgm^(2) .If the angular momentum of the particle about the axis is 0.4kgm^(2)/s ,then what is the rotational kinetic energy of the particle?

When a constant torque is applied to a flywheel at rest it angular velocity increases by 10 rad/s in 2 s: Calculate the torque applied if the moment of inertia of the flywheel about the axis of rotation is 200 kg m^(2) .

A flywheel is rotating at an angular speed of 150 rpm. If the moment of inertia of the flywheel somehow decreases from 10kgm^(2) to 4kgm^(2) , then what will be the new angular speed of the flywheel?

Moment of inertia of a disc about its own axis is I. Its moment of inertia about a tangential axis in its plane is