If `P={x in R : f(x)=0}` and `Q={x in R : g(x)=0 }`, then `PuuQ` is

If f : R rarr R and g: R rarr R are given by f(x)=|x| and g(x)={x} for each x in R , then |x in R : g(f(x)) le f(g(x))}=

Let g'(x)>0 and f'(x)<0AA x in R, then

If f : R to R and g: R to R are given by f(x) =|x| and g(x) =[x] for each x in R , then {x in R: g(f(x)) le f(g(x))} =

Let f(x)= {(1, x in Q), (0, x in R-Q):} and g(x)= {(1, x in R-Q), (0, x in Q):} , find (f+g)(x) and (fg)(x).

If f:R rarr R and g:R rarr R is given by f(x)=|x| and g(x)=[x] for each x in R then {x in R:g(f(x))<=f(g(x))}

If f:R->R and g:R->R is given by f(x) =|x| and g(x)=[x] for each x in R then {x in R:g(f(x))le f(g(x))}

If f:R->R and g:R->R is given by f(x) =|x| and g(x)=[x] for each x in R then {x in R:g(f(x))le f(g(x))}