10 ml of gaseous hydrocarbon on combution gives 20ml of `CO_(2)` and 30ml of `H_(2)O(g)`. The hydrocarbon is :-

10 ml of gaseous hydrocarbon on combustion gives 40 ml of CO_2_(g) and 50 ml of H_2O (vap) . The hydrocarbon is :

10mL of gaseous hydrocarbon on combustion gives 40ml of CO_(2)(g) and 50mL of H_(2)O (vapour) The hydrocarbon is .

10mL of gaseous hydrocarbon on combustion gives 40ml of CO_(2)(g) and 50mL of H_(2)O (vapour) The hydrocarbon is .

10ml of a gaseous hydrocarbon on combustion gives 40ml of CO_(2) and 50ml of H_(2)O vapour under the same conditions. The hydrocarbon is

10 ml of hydrocarbon requries 55 ml of oxygen for complete combustion producing 40 ml of CO_(2) . The formula of the hydrocarbon is:

10 ml of hydrocarbon requries 55 ml of oxygen for complete combustion producing 40 ml of CO_(2) . The formula of the hydrocarbon is:

500 ml of a gaseous hydrocarbon when burnt in excess of O_(2) gave 2.0litres of CO_(2) and 2.5 litres of water vapours under same conditions. molecular formula of the hydrocarbon is:-

500 ml of a gaseous hydrocarbon when burnt in excess of O_(2) gave 2.0litres of CO_(2) and 2.5 litres of water vapours under same conditions. molecular formula of the hydrocarbon is:-