If `y = y(x)` is the solution of the differential equation,`x (dy)/(dx) + 5y = 10x^5, x > 0` satisfying `y(1) = 2` then range of `y(x)` for `x > 0` is:

The solution of the differential equation x(dy)/(dx) + 2y = x^2 (X ne 0) with y(1) =1, is :

The solution of the differential equation x(dy)/(dx) + 2y = x^2 (X ne 0) with y(1) =1, is :

Solution of the differential equation y dx+(x-y^(2))dy=0 is

(5) The solution of the differential equation (y-xy^(2))dx-(x+x^(2)y)dy=0

Let y be the solution of the differential equation x(dy)/(dx)=(y^(2))/(1-y log x) satisfying y(1)=1 then y satisfies

If y = y (x) is the solution of the differential equation (5 + e^(x))/(2 + y) * (dy)/(dx) + e^(x) = 0 satisfying y(0) = 1 , then a value of y (log _(e) 13) is :