Let `f` be a positive function. If `I_1 = int_(1-k)^k x f[x(1-x)]\ dx` and `I_2 = int_(1-k)^k f[x(1-x)]\ dx,` where `2k-1 gt 0.` Then `I_1/I_2` is

Let f be a positive function. Let I_(1)=int_(1-k)^(k)x f[x(1-x)]dx , I_(2)=int_(1-k)^(k)f[x(1-x)]dx , where 2k-1gt0 . Then (I_(1))/(I_(2)) is

Let f be a positive function. Let I_1=int_(1-k)^k xf([x(1-x)])dx , I_2=int_(1-k)^kf[x(1-x)]dx ,w h e r e2k-1> 0. T h e n(I_1)/(I_2)i s 2 (b) k (c) 1/2 (d) 1

Let f be a positive function. Let I_1=int_(1-k)^k xf([x(1-x)])dx , I_2=int_(1-k)^kf[x(1-x)]dx ,w h e r e2k-1> 0. T h e n(I_1)/(I_2)i s 2 (b) k (c) 1/2 (d) 1

Let f be a positive function. Let I_1=int_(1-k)^k xf([x(1-x)])dx , I_2=int_(1-k)^kf[x(1-x)]dx ,w h e r e2k-1> 0. T h e n(I_1)/(I_2)i s 2 (b) k (c) 1/2 (d) 1

Let f be a positive function.Let I_(1)=int_(1-k)^(k)xf([x(1-x)])dxI_(2)=int_(1-k)^(k)f[x(1-x)]dx, where 2k-1>0. Then (I_(1))/(I_(2))is 2(b) k(c)(1)/(2) (d) 1

If I_(1)=int_(1-x)^(k) x sin{x(1-x)}dx and I_(2)=int_(1-x)^(k) sin{x(1-x)}dx , then

Let f be a function defined by f(x)=4^x/(4^x+2) I_1=int_(f(1-a))^(f(a)) xf{x(1-x)}dx and I_2=int_(f(1-a))^(f(a)) f{x(1-x)}dx where 2a-1gt0 then I_1:I_2 is (A) 2 (B) k (C) 1/2 (D) 1

Let f be a function defined by f(x)=4^x/(4^x+2) I_1=int_(f(1-a))^(f(a)) xf{x(1-x)}dx and I_2=int_(f(1-a))^(f(a)) f{x(1-x)}dx where 2a-1gt0 then I_1:I_2 is (A) 2 (B) k (C) 1/2 (D) 1