`sin{cot^(-1)[cos(tan^(-1)x)]}=....`

sin {cot^(-1)[tan (cos^(-1)x)]=

"If"sin{cot^(-1)(x+1)}=cos(tan^(-1)x), then find x.

If sin{cot^(-1)(x+1)}=cos(tan^(-1)x), then find x

If sin{cot^(-1)(x+1)}=cos(tan^(-1)x), then find x.

f(x)=sin{cot^(-1)(x+1)}-cos(tan^(-1)x), The value of x for which f(x) = 0 is

f(x)=sin{cot^(-1)(x+1)}-cos(tan^(-1)x), a=costan^(-1)sincot^(-1)x, b=cos(2cos^(-1)x+sin^(-1)x) If f(x)=0 then a^(2)=

f(x)=sin{cot^(-1)(x+1)}-cos(tan^(-1)x), a=costan^(-1)sincot^(-1)x, b=cos(2cos^(-1)x+sin^(-1)x) If a^(2)=26//51," then "b^(2)=

If sin{cot^-1(x+1)}="cos"(tan^(-1)x), then find x