Home
Class 12
CHEMISTRY
OXIDATION NO. METHOD|EQUIVALENCE CONCEPT...

OXIDATION NO. METHOD|EQUIVALENCE CONCEPT#!#N FACTOR CALCULATION

Promotional Banner

Similar Questions

Explore conceptually related problems

N-Factor & Its Calculation

Calculation Of n Factor|Calculation Of n Factor For Redox Reactions|Normality|Law Of Equivalence|OMR

Calculation OF N-Factor for Oxidising agent, N-Factor when O.N. OF More than One Element Changes

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. One mole of As_(2)S_(3) is oxidised by HNO_(3) to H_(3)AsO_(4) and H_(2)SO_(4).HNO_(3) is converted into NO . The moles of HNO_(3) required are:

Stoichiometry - Concept Of Gram Equivalent 1 - Copy

Concept OF equivalent weight || old concept and new concept,introduction OF 'n' factor || calculation OF 'n' factor [A/B/C/N/V] || calculation OF 'n' factor OF Base/ Arrhenius Base

Concept Of Oxidation Number|Rules For Governing Oxidation Number|Calculation Of Oxidation State|OMR

Concept Of Oxidation Number|Rules For Governing Oxidation Number|Calculation Of Oxidation State|OMR

Some Important Oxidizing Agents And Reducing Agents|Equivalent Concept (Mole II)|OMR

Concept Of Oxidation Number|Concept Of Maximum And Minimum Oxidation State|Paradox Of Fractional Oxidation Number|Oxidation And Reduction|OMR